State the dimension of the nucleus from the R | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the Rutherford alpha-particle scattering experiment,the distance of closest approach is used to estimate the size of the nucleus.For an alpha p

Vedclass · Accepted Answer

$10^{-15} \ m$

Vedclass · Answer

(B) In the Rutherford alpha-particle scattering experiment,the distance of closest approach is used to estimate the size of the nucleus.For an alpha particle with kinetic energy $K$ directed towards the center of the nucleus with atomic number $Z$,the distance of closest approach $r_0$ is given by $r_0 = \frac{1}{4\pi\epsilon_0} \frac{2Ze^2}{K}$.Experimental results indicate that the dimension of the nucleus is of the order of $10^{-15} \ m$ (or $1 \ fm$).

State the dimension of the nucleus from the Rutherford experiment.

Similar Questions

$A$ free neutron decays into a proton,but a free proton does not decay into a neutron. This is because

For effective nuclear forces,the distance should be

Consider the following nuclear reactions:
$I$. ${ }_{7}^{14} N +{ }_{2}^{4} He \longrightarrow{ }_{8}^{17} O + X$
$II$. ${ }_{4}^{9} Be +{ }_{2}^{4} He \longrightarrow{ }_{6}^{12} C + Y$
Then,

In the equation ${ }_{13}^{27} Al + { }_2^4 He \longrightarrow { }_{15}^{30} P + X$,the correct symbol for $X$ is:

Which is the correct unit for measuring nuclear radii?

Vedclass Test Series

Exam Paper Generator

Online Exam Module